The apparent and absolute magnitude, spectral type, distance (LY) are given.
Is there a correlation between luminosity and temperature of the star, i.e. do hotter stars have higher luminosities?|||When a star is in the main sequence stage (the first stage, which the sun is currently in), brightness generally correlates with temperature. In later stages (red giant, white dwarf, neutron star, black hole, etc), brightness depends on age and mass, not temperature. A small white dwarf is hotter than a red giant, but a red giant is brighter because of its size (and mass). During their main sequence stage, the white dwarf might have been the more massive and the brighter. Absolute magnitute determines a star's absolute brightness. It's the visual magnitude at an absolute distance of 10 parsecs. Calculating absolute and visual magnitude is a bit complicated. For example, absolute magnitude = visual magnitue - ((log (distance in parsecs ^2 / 10 parsecs ^ 2)) / log (10 ^ (2/5))).|||Stellar brightness (Luminosity)
Brightness is related to the energy we detect
With your eye or another detector
The energy
Measured in
Joules/sec
1J/s = 1 Watt
We have discussed the apparent visual magnitude
How stars look relative to one another from earth
We called this apparent visual magnitude (mv)
Human eye goes to about 6th mag
But this has nothing to do with how bright a star actually is
Distance
Dust
Size of star
Color
All affect brightness
To begin our in-depth study of stars we need to be able to compare stars directly
We need absolute magnitude (not just apparent mag)
Absolute visual magnitude (Mv)
If all stars were the same distance away, say 10 parsecs
We could compare them objectively
Mv is related to mv and distance from earth
mv 鈥揗v = -5 +5log10(d)
mv apparent visual magnitude
Mv is the absolute visual mag if the star were 10 parsecs away
d is the distance to the star in parsecs
Example
Betelgeuse in Orion is 427 ly away with mv=0.45
427 ly = 130 parsecs
0.45- Mv = -5 + 5log10(130)
0.45- Mv = -5 + 5(2.11)
0.45 鈥?Mv=5.57
Mv= -5.12
Absolute magnitude of the Sun
4.78
if it were 10 parsecs away
This is still the visual magnitude
Remember stars emit radiation outside the visible range
Determining stellar Luminosity
Now that we have the absolute visual magnitude
We can compare other stars to the Sun
The brightest stars
Mv = -8
100,000 time more light than the Sun
Dimmest
Mv =15
10,000 time less than the Sun
Let鈥檚 take this a step further
Luminosity 鈥?the amount of energy emitted by a star
Depends on two things
Temperature
Size
Energy radiated by a black body
Stefan-Boltzmann Law
E = sT4
E is energy emitted in 1 sec per m2 (J/sec/m2)
T is temperature
s is Stefan-Boltzmann constant
5.67 x 10-8 J/m2 sec degree4
Energy goes up dramatically as T goes up
3000潞K
4,592,700 J/s/m2
6000潞K
73,483,200 J/s/m2
E = sT4
L = surface area x sT4
Area of a sphere
4pR2
and
L = 4pR2 sT4
We can simplify
Now we can determine the Luminosity of a star relative to the sun which we know
Radius
We can also use this formula to find radius
Pick a star
Hamal in Aries, mv = 2.0
Mv = 0.472
(Sun) 4.78 - (Hamal)0.472 = 4.3 magnitudes brighter than the sun
2.5124.3 = 52.5 times the luminosity of the sun
Hamal is a K2 star 4000掳K
4000/5800 = 0.689655172 times the suns temp
52.5 = 0.23
Ro
Radius of Hamal is 15.1 times the Sun鈥檚 radius
So now we know luminosity and Radius and Temp|||--|||Look at it
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment