A typical neutron star has five times the mass of our Sun and a radius of about 10 km. If you were standing on the surface of this neutron star, what would be the acceleration due to gravity there? The mass of the sun is 2.0 * 10^30 kg.|||F = ma
for gravity, this is equal to
F = mg
Set this equal to F = [GmM/r虏]
mg = [GmM/r虏]
the "m" cancels
g = GM/r虏
plug in the numbers
M = 5 x 10^30 kg
= 1 x10^31kg
g = [ (6.67 x 10^-11 kg m/s虏 m虏/kg)( 1 x10^31kg) ] / [1 x 10^4 m]虏
Don't have a calculator but that's how you do it anyway|||a = Gm/r虏
a is acceleration from mass attraction in m/s虏
G = 6.67e-11 m鲁/kgs虏
a = (6.67e-11)(5*2e30) / (10000)虏 = 6.67e12 m/s虏
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